(3x+4)/2=(2x-2)/4

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Solution for (3x+4)/2=(2x-2)/4 equation: 



(3x+4)/2=(2x-2)/4

We move all terms to the left:

(3x+4)/2-((2x-2)/4)=0

We calculate fractions


3x/()+(-((2x-2)*2)/()=0



We calculate terms in parentheses: +(-((2x-2)*2)/(), so:

-((2x-2)*2)/(

We multiply all the terms by the denominator


-((2x-2)*2)



We calculate terms in parentheses: -((2x-2)*2), so:

(2x-2)*2

We multiply parentheses

4x-4

Back to the equation:

-(4x-4)



We get rid of parentheses

-4x+4

Back to the equation:

+(-4x+4)



We get rid of parentheses

3x/()-4x+4=0

We multiply all the terms by the denominator


3x-4x*()+4*()=0

We add all the numbers together, and all the variables

3x-4x*()=0

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