(3x+4)/2=(5x+3)/3

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Solution for (3x+4)/2=(5x+3)/3 equation: 



(3x+4)/2=(5x+3)/3

We move all terms to the left:

(3x+4)/2-((5x+3)/3)=0

We calculate fractions


3x/()+(-((5x+3)*2)/()=0



We calculate terms in parentheses: +(-((5x+3)*2)/(), so:

-((5x+3)*2)/(

We multiply all the terms by the denominator


-((5x+3)*2)



We calculate terms in parentheses: -((5x+3)*2), so:

(5x+3)*2

We multiply parentheses

10x+6

Back to the equation:

-(10x+6)



We get rid of parentheses

-10x-6

Back to the equation:

+(-10x-6)



We get rid of parentheses

3x/()-10x-6=0

We multiply all the terms by the denominator


3x-10x*()-6*()=0

We add all the numbers together, and all the variables

3x-10x*()=0

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