(3x+4)/5=2(3x+4)/10

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Solution for (3x+4)/5=2(3x+4)/10 equation: 



(3x+4)/5=2(3x+4)/10

We move all terms to the left:

(3x+4)/5-(2(3x+4)/10)=0

We calculate fractions


3x/()+(-(2(3x+4)*5)/()=0



We calculate terms in parentheses: +(-(2(3x+4)*5)/(), so:

-(2(3x+4)*5)/(

We multiply all the terms by the denominator


-(2(3x+4)*5)



We calculate terms in parentheses: -(2(3x+4)*5), so:

2(3x+4)*5

We multiply parentheses

30x+40

Back to the equation:

-(30x+40)



We get rid of parentheses

-30x-40

Back to the equation:

+(-30x-40)



We get rid of parentheses

3x/()-30x-40=0

We multiply all the terms by the denominator


3x-30x*()-40*()=0

We add all the numbers together, and all the variables

3x-30x*()=0

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