(3x+4)/6+(x+18)/6=(x+8)/4

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Solution for (3x+4)/6+(x+18)/6=(x+8)/4 equation: 



(3x+4)/6+(x+18)/6=(x+8)/4

We move all terms to the left:

(3x+4)/6+(x+18)/6-((x+8)/4)=0

We calculate fractions


4x/()+(-((x+8)*6)/()=0



We calculate terms in parentheses: +(-((x+8)*6)/(), so:

-((x+8)*6)/(

We multiply all the terms by the denominator


-((x+8)*6)



We calculate terms in parentheses: -((x+8)*6), so:

(x+8)*6

We multiply parentheses

6x+48

Back to the equation:

-(6x+48)



We get rid of parentheses

-6x-48

Back to the equation:

+(-6x-48)



We get rid of parentheses

4x/()-6x-48=0

We multiply all the terms by the denominator


4x-6x*()-48*()=0

We add all the numbers together, and all the variables

4x-6x*()=0

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