(3x+4)=(2x+16)

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Solution for (3x+4)=(2x+16) equation:



(3x+4)=(2x+16)
We move all terms to the left:
(3x+4)-((2x+16))=0
We get rid of parentheses
3x-((2x+16))+4=0
We calculate terms in parentheses: -((2x+16)), so:
(2x+16)
We get rid of parentheses
2x+16
Back to the equation:
-(2x+16)
We get rid of parentheses
3x-2x-16+4=0
We add all the numbers together, and all the variables
x-12=0
We move all terms containing x to the left, all other terms to the right
x=12

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