(3x+4)=(3x+19)+(10x-1)

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Solution for (3x+4)=(3x+19)+(10x-1) equation: 



(3x+4)=(3x+19)+(10x-1)

We move all terms to the left:

(3x+4)-((3x+19)+(10x-1))=0

We get rid of parentheses

3x-((3x+19)+(10x-1))+4=0



We calculate terms in parentheses: -((3x+19)+(10x-1)), so:

(3x+19)+(10x-1)

We get rid of parentheses

3x+10x+19-1

We add all the numbers together, and all the variables

13x+18

Back to the equation:

-(13x+18)



We get rid of parentheses

3x-13x-18+4=0

We add all the numbers together, and all the variables

-10x-14=0

We move all terms containing x to the left, all other terms to the right

-10x=14

x=14/-10

x=-1+2/5

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