(3x+4)=2(x-1)+10

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Solution for (3x+4)=2(x-1)+10 equation:



(3x+4)=2(x-1)+10
We move all terms to the left:
(3x+4)-(2(x-1)+10)=0
We get rid of parentheses
3x-(2(x-1)+10)+4=0
We calculate terms in parentheses: -(2(x-1)+10), so:
2(x-1)+10
We multiply parentheses
2x-2+10
We add all the numbers together, and all the variables
2x+8
Back to the equation:
-(2x+8)
We get rid of parentheses
3x-2x-8+4=0
We add all the numbers together, and all the variables
x-4=0
We move all terms containing x to the left, all other terms to the right
x=4

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