(3x+4)=2(x-1)+10

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Solution for (3x+4)=2(x-1)+10 equation: 



(3x+4)=2(x-1)+10

We move all terms to the left:

(3x+4)-(2(x-1)+10)=0

We get rid of parentheses

3x-(2(x-1)+10)+4=0



We calculate terms in parentheses: -(2(x-1)+10), so:

2(x-1)+10

We multiply parentheses

2x-2+10

We add all the numbers together, and all the variables

2x+8

Back to the equation:

-(2x+8)



We get rid of parentheses

3x-2x-8+4=0

We add all the numbers together, and all the variables

x-4=0

We move all terms containing x to the left, all other terms to the right

x=4

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