(3x+4-x)=16

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Solution for (3x+4-x)=16 equation: 



(3x+4-x)=16

We move all terms to the left:

(3x+4-x)-(16)=0

We add all the numbers together, and all the variables

(2x+4)-16=0

We get rid of parentheses

2x+4-16=0

We add all the numbers together, and all the variables

2x-12=0

We move all terms containing x to the left, all other terms to the right

2x=12

x=12/2

x=6

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