(3x+40)+(3x-17)+(x-40)+(2x-5)=180

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Solution for (3x+40)+(3x-17)+(x-40)+(2x-5)=180 equation: 



(3x+40)+(3x-17)+(x-40)+(2x-5)=180

We move all terms to the left:

(3x+40)+(3x-17)+(x-40)+(2x-5)-(180)=0

We get rid of parentheses

3x+3x+x+2x+40-17-40-5-180=0

We add all the numbers together, and all the variables

9x-202=0

We move all terms containing x to the left, all other terms to the right

9x=202

x=202/9

x=22+4/9

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