(3x+40)=(5x+28)

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Solution for (3x+40)=(5x+28) equation: 



(3x+40)=(5x+28)

We move all terms to the left:

(3x+40)-((5x+28))=0

We get rid of parentheses

3x-((5x+28))+40=0



We calculate terms in parentheses: -((5x+28)), so:

(5x+28)

We get rid of parentheses

5x+28

Back to the equation:

-(5x+28)



We get rid of parentheses

3x-5x-28+40=0

We add all the numbers together, and all the variables

-2x+12=0

We move all terms containing x to the left, all other terms to the right

-2x=-12

x=-12/-2

x=+6

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