(3x+43)=(9x-5)

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Solution for (3x+43)=(9x-5) equation: 



(3x+43)=(9x-5)

We move all terms to the left:

(3x+43)-((9x-5))=0

We get rid of parentheses

3x-((9x-5))+43=0



We calculate terms in parentheses: -((9x-5)), so:

(9x-5)

We get rid of parentheses

9x-5

Back to the equation:

-(9x-5)



We get rid of parentheses

3x-9x+5+43=0

We add all the numbers together, and all the variables

-6x+48=0

We move all terms containing x to the left, all other terms to the right

-6x=-48

x=-48/-6

x=+8

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