(3x+44)+(4x-3)+x=180

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Solution for (3x+44)+(4x-3)+x=180 equation: 



(3x+44)+(4x-3)+x=180

We move all terms to the left:

(3x+44)+(4x-3)+x-(180)=0

We add all the numbers together, and all the variables

x+(3x+44)+(4x-3)-180=0

We get rid of parentheses

x+3x+4x+44-3-180=0

We add all the numbers together, and all the variables

8x-139=0

We move all terms containing x to the left, all other terms to the right

8x=139

x=139/8

x=17+3/8

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