(3x+49)=(6x+10)

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Solution for (3x+49)=(6x+10) equation: 



(3x+49)=(6x+10)

We move all terms to the left:

(3x+49)-((6x+10))=0

We get rid of parentheses

3x-((6x+10))+49=0



We calculate terms in parentheses: -((6x+10)), so:

(6x+10)

We get rid of parentheses

6x+10

Back to the equation:

-(6x+10)



We get rid of parentheses

3x-6x-10+49=0

We add all the numbers together, and all the variables

-3x+39=0

We move all terms containing x to the left, all other terms to the right

-3x=-39

x=-39/-3

x=+13

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