(3x+5)(-2x+10)=0

Solution for (3x+5)(-2x+10)=0 equation:

(3x+5)(-2x+10)=0

We multiply parentheses ..

(-6x^2+30x-10x+50)=0

We get rid of parentheses

-6x^2+30x-10x+50=0

We add all the numbers together, and all the variables

-6x^2+20x+50=0

a = -6; b = 20; c = +50;
Δ = b2-4ac
Δ = 202-4·(-6)·50
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1600}=40$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-40}{2*-6}=\frac{-60}{-12}
=+5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+40}{2*-6}=\frac{20}{-12}
=-1+2/3
$