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(3x+5)(2x)=x
We move all terms to the left:
(3x+5)(2x)-(x)=0
We add all the numbers together, and all the variables
-1x+(3x+5)2x=0
We multiply parentheses
6x^2-1x+10x=0
We add all the numbers together, and all the variables
6x^2+9x=0
a = 6; b = 9; c = 0;
Δ = b2-4ac
Δ = 92-4·6·0
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{81}=9$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-9}{2*6}=\frac{-18}{12} =-1+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+9}{2*6}=\frac{0}{12} =0 $
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