(3x+5)(2x+1)=(6x+5)(x-3)+7

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Solution for (3x+5)(2x+1)=(6x+5)(x-3)+7 equation:



(3x+5)(2x+1)=(6x+5)(x-3)+7
We move all terms to the left:
(3x+5)(2x+1)-((6x+5)(x-3)+7)=0
We multiply parentheses ..
(+6x^2+3x+10x+5)-((6x+5)(x-3)+7)=0
We calculate terms in parentheses: -((6x+5)(x-3)+7), so:
(6x+5)(x-3)+7
We multiply parentheses ..
(+6x^2-18x+5x-15)+7
We get rid of parentheses
6x^2-18x+5x-15+7
We add all the numbers together, and all the variables
6x^2-13x-8
Back to the equation:
-(6x^2-13x-8)
We get rid of parentheses
6x^2-6x^2+3x+10x+13x+5+8=0
We add all the numbers together, and all the variables
26x+13=0
We move all terms containing x to the left, all other terms to the right
26x=-13
x=-13/26
x=-1/2

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