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(3x+5)(2x+6)=0
We multiply parentheses ..
(+6x^2+18x+10x+30)=0
We get rid of parentheses
6x^2+18x+10x+30=0
We add all the numbers together, and all the variables
6x^2+28x+30=0
a = 6; b = 28; c = +30;
Δ = b2-4ac
Δ = 282-4·6·30
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{64}=8$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(28)-8}{2*6}=\frac{-36}{12} =-3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(28)+8}{2*6}=\frac{-20}{12} =-1+2/3 $
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