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(3x+5)(2x-1)=70
We move all terms to the left:
(3x+5)(2x-1)-(70)=0
We multiply parentheses ..
(+6x^2-3x+10x-5)-70=0
We get rid of parentheses
6x^2-3x+10x-5-70=0
We add all the numbers together, and all the variables
6x^2+7x-75=0
a = 6; b = 7; c = -75;
Δ = b2-4ac
Δ = 72-4·6·(-75)
Δ = 1849
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1849}=43$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-43}{2*6}=\frac{-50}{12} =-4+1/6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+43}{2*6}=\frac{36}{12} =3 $
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