(3x+5)(2x-1)=x(6x-1)-16

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Solution for (3x+5)(2x-1)=x(6x-1)-16 equation: 



(3x+5)(2x-1)=x(6x-1)-16

We move all terms to the left:

(3x+5)(2x-1)-(x(6x-1)-16)=0

We multiply parentheses ..

(+6x^2-3x+10x-5)-(x(6x-1)-16)=0



We calculate terms in parentheses: -(x(6x-1)-16), so:

x(6x-1)-16

We multiply parentheses

6x^2-1x-16

Back to the equation:

-(6x^2-1x-16)



We get rid of parentheses

6x^2-6x^2-3x+10x+1x-5+16=0

We add all the numbers together, and all the variables

8x+11=0

We move all terms containing x to the left, all other terms to the right

8x=-11

x=-11/8

x=-1+3/8

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