(3x+5)(3x+2)=(x-10)

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Solution for (3x+5)(3x+2)=(x-10) equation: 



(3x+5)(3x+2)=(x-10)

We move all terms to the left:

(3x+5)(3x+2)-((x-10))=0

We multiply parentheses ..

(+9x^2+6x+15x+10)-((x-10))=0



We calculate terms in parentheses: -((x-10)), so:

(x-10)

We get rid of parentheses

x-10

Back to the equation:

-(x-10)



We get rid of parentheses

9x^2+6x+15x-x+10+10=0

We add all the numbers together, and all the variables

9x^2+20x+20=0

a = 9; b = 20; c = +20;
Δ = b2-4ac
Δ = 202-4·9·20
Δ = -320
Delta is less than zero, so there is no solution for the equation

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