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(3x+5)(4x-1)=(6x-3)(2x+7)
We move all terms to the left:
(3x+5)(4x-1)-((6x-3)(2x+7))=0
We multiply parentheses ..
(+12x^2-3x+20x-5)-((6x-3)(2x+7))=0
We calculate terms in parentheses: -((6x-3)(2x+7)), so:We get rid of parentheses
(6x-3)(2x+7)
We multiply parentheses ..
(+12x^2+42x-6x-21)
We get rid of parentheses
12x^2+42x-6x-21
We add all the numbers together, and all the variables
12x^2+36x-21
Back to the equation:
-(12x^2+36x-21)
12x^2-12x^2-3x+20x-36x-5+21=0
We add all the numbers together, and all the variables
-19x+16=0
We move all terms containing x to the left, all other terms to the right
-19x=-16
x=-16/-19
x=16/19
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