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(3x+5)(4x-2)=0
We multiply parentheses ..
(+12x^2-6x+20x-10)=0
We get rid of parentheses
12x^2-6x+20x-10=0
We add all the numbers together, and all the variables
12x^2+14x-10=0
a = 12; b = 14; c = -10;
Δ = b2-4ac
Δ = 142-4·12·(-10)
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{676}=26$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-26}{2*12}=\frac{-40}{24} =-1+2/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+26}{2*12}=\frac{12}{24} =1/2 $
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