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(3x+5)(3x+5)=7
We move all terms to the left:
(3x+5)(3x+5)-(7)=0
We multiply parentheses ..
(+9x^2+15x+15x+25)-7=0
We get rid of parentheses
9x^2+15x+15x+25-7=0
We add all the numbers together, and all the variables
9x^2+30x+18=0
a = 9; b = 30; c = +18;
Δ = b2-4ac
Δ = 302-4·9·18
Δ = 252
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{252}=\sqrt{36*7}=\sqrt{36}*\sqrt{7}=6\sqrt{7}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-6\sqrt{7}}{2*9}=\frac{-30-6\sqrt{7}}{18} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+6\sqrt{7}}{2*9}=\frac{-30+6\sqrt{7}}{18} $
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