(3x+5)+(21x+3)=176

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Solution for (3x+5)+(21x+3)=176 equation: 



(3x+5)+(21x+3)=176

We move all terms to the left:

(3x+5)+(21x+3)-(176)=0

We get rid of parentheses

3x+21x+5+3-176=0

We add all the numbers together, and all the variables

24x-168=0

We move all terms containing x to the left, all other terms to the right

24x=168

x=168/24

x=7

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