(3x+5)+(2x+1)=5(x-1)+10

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Solution for (3x+5)+(2x+1)=5(x-1)+10 equation:


Simplifying
(3x + 5) + (2x + 1) = 5(x + -1) + 10

Reorder the terms:
(5 + 3x) + (2x + 1) = 5(x + -1) + 10

Remove parenthesis around (5 + 3x)
5 + 3x + (2x + 1) = 5(x + -1) + 10

Reorder the terms:
5 + 3x + (1 + 2x) = 5(x + -1) + 10

Remove parenthesis around (1 + 2x)
5 + 3x + 1 + 2x = 5(x + -1) + 10

Reorder the terms:
5 + 1 + 3x + 2x = 5(x + -1) + 10

Combine like terms: 5 + 1 = 6
6 + 3x + 2x = 5(x + -1) + 10

Combine like terms: 3x + 2x = 5x
6 + 5x = 5(x + -1) + 10

Reorder the terms:
6 + 5x = 5(-1 + x) + 10
6 + 5x = (-1 * 5 + x * 5) + 10
6 + 5x = (-5 + 5x) + 10

Reorder the terms:
6 + 5x = -5 + 10 + 5x

Combine like terms: -5 + 10 = 5
6 + 5x = 5 + 5x

Add '-5x' to each side of the equation.
6 + 5x + -5x = 5 + 5x + -5x

Combine like terms: 5x + -5x = 0
6 + 0 = 5 + 5x + -5x
6 = 5 + 5x + -5x

Combine like terms: 5x + -5x = 0
6 = 5 + 0
6 = 5

Solving
6 = 5

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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