(3x+5)+(3x+18)=(10x+9)

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Solution for (3x+5)+(3x+18)=(10x+9) equation: 



(3x+5)+(3x+18)=(10x+9)

We move all terms to the left:

(3x+5)+(3x+18)-((10x+9))=0

We get rid of parentheses

3x+3x-((10x+9))+5+18=0



We calculate terms in parentheses: -((10x+9)), so:

(10x+9)

We get rid of parentheses

10x+9

Back to the equation:

-(10x+9)



We add all the numbers together, and all the variables

6x-(10x+9)+23=0

We get rid of parentheses

6x-10x-9+23=0

We add all the numbers together, and all the variables

-4x+14=0

We move all terms containing x to the left, all other terms to the right

-4x=-14

x=-14/-4

x=3+1/2

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