(3x+5)+(x+2)=4(x-1)+7

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Solution for (3x+5)+(x+2)=4(x-1)+7 equation:


Simplifying
(3x + 5) + (x + 2) = 4(x + -1) + 7

Reorder the terms:
(5 + 3x) + (x + 2) = 4(x + -1) + 7

Remove parenthesis around (5 + 3x)
5 + 3x + (x + 2) = 4(x + -1) + 7

Reorder the terms:
5 + 3x + (2 + x) = 4(x + -1) + 7

Remove parenthesis around (2 + x)
5 + 3x + 2 + x = 4(x + -1) + 7

Reorder the terms:
5 + 2 + 3x + x = 4(x + -1) + 7

Combine like terms: 5 + 2 = 7
7 + 3x + x = 4(x + -1) + 7

Combine like terms: 3x + x = 4x
7 + 4x = 4(x + -1) + 7

Reorder the terms:
7 + 4x = 4(-1 + x) + 7
7 + 4x = (-1 * 4 + x * 4) + 7
7 + 4x = (-4 + 4x) + 7

Reorder the terms:
7 + 4x = -4 + 7 + 4x

Combine like terms: -4 + 7 = 3
7 + 4x = 3 + 4x

Add '-4x' to each side of the equation.
7 + 4x + -4x = 3 + 4x + -4x

Combine like terms: 4x + -4x = 0
7 + 0 = 3 + 4x + -4x
7 = 3 + 4x + -4x

Combine like terms: 4x + -4x = 0
7 = 3 + 0
7 = 3

Solving
7 = 3

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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