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(3x+5)+x+(x+20)=180
We move all terms to the left:
(3x+5)+x+(x+20)-(180)=0
We add all the numbers together, and all the variables
x+(3x+5)+(x+20)-180=0
We get rid of parentheses
x+3x+x+5+20-180=0
We add all the numbers together, and all the variables
5x-155=0
We move all terms containing x to the left, all other terms to the right
5x=155
x=155/5
x=31
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