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(3x+5)/(3-2x)=5/3
We move all terms to the left:
(3x+5)/(3-2x)-(5/3)=0
Domain of the equation: (3-2x)!=0We add all the numbers together, and all the variables
We move all terms containing x to the left, all other terms to the right
-2x!=-3
x!=-3/-2
x!=1+1/2
x∈R
(3x+5)/(-2x+3)-(+5/3)=0
We get rid of parentheses
(3x+5)/(-2x+3)-5/3=0
We calculate fractions
(9x+15)/(-6x+9)+(10x-15)/(-6x+9)=0
We multiply all the terms by the denominator
(9x+15)+(10x-15)=0
We get rid of parentheses
9x+10x+15-15=0
We add all the numbers together, and all the variables
19x=0
x=0/19
x=0
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