(3x+5)/2=(4x+10)/3

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Solution for (3x+5)/2=(4x+10)/3 equation: 



(3x+5)/2=(4x+10)/3

We move all terms to the left:

(3x+5)/2-((4x+10)/3)=0

We calculate fractions


3x/()+(-((4x+10)*2)/()=0



We calculate terms in parentheses: +(-((4x+10)*2)/(), so:

-((4x+10)*2)/(

We multiply all the terms by the denominator


-((4x+10)*2)



We calculate terms in parentheses: -((4x+10)*2), so:

(4x+10)*2

We multiply parentheses

8x+20

Back to the equation:

-(8x+20)



We get rid of parentheses

-8x-20

Back to the equation:

+(-8x-20)



We get rid of parentheses

3x/()-8x-20=0

We multiply all the terms by the denominator


3x-8x*()-20*()=0

We add all the numbers together, and all the variables

3x-8x*()=0

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