(3x+5)/2=(4x-3)/3

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Solution for (3x+5)/2=(4x-3)/3 equation: 



(3x+5)/2=(4x-3)/3

We move all terms to the left:

(3x+5)/2-((4x-3)/3)=0

We calculate fractions


3x/()+(-((4x-3)*2)/()=0



We calculate terms in parentheses: +(-((4x-3)*2)/(), so:

-((4x-3)*2)/(

We multiply all the terms by the denominator


-((4x-3)*2)



We calculate terms in parentheses: -((4x-3)*2), so:

(4x-3)*2

We multiply parentheses

8x-6

Back to the equation:

-(8x-6)



We get rid of parentheses

-8x+6

Back to the equation:

+(-8x+6)



We get rid of parentheses

3x/()-8x+6=0

We multiply all the terms by the denominator


3x-8x*()+6*()=0

We add all the numbers together, and all the variables

3x-8x*()=0

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