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(3x+5)/3-(4-x)/6=x
We move all terms to the left:
(3x+5)/3-(4-x)/6-(x)=0
We add all the numbers together, and all the variables
(3x+5)/3-(-1x+4)/6-x=0
We add all the numbers together, and all the variables
-1x+(3x+5)/3-(-1x+4)/6=0
We calculate fractions
There is no solution for this equation
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