(3x+5)/3=(18x+5)/7

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Solution for (3x+5)/3=(18x+5)/7 equation:



(3x+5)/3=(18x+5)/7
We move all terms to the left:
(3x+5)/3-((18x+5)/7)=0
We calculate fractions
3x/()+(-((18x+5)*3)/()=0
We calculate terms in parentheses: +(-((18x+5)*3)/(), so:
-((18x+5)*3)/(
We multiply all the terms by the denominator
-((18x+5)*3)
We calculate terms in parentheses: -((18x+5)*3), so:
(18x+5)*3
We multiply parentheses
54x+15
Back to the equation:
-(54x+15)
We get rid of parentheses
-54x-15
Back to the equation:
+(-54x-15)
We get rid of parentheses
3x/()-54x-15=0
We multiply all the terms by the denominator
3x-54x*()-15*()=0
We add all the numbers together, and all the variables
3x-54x*()=0

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