(3x+5)/6+(x-11)/6=(x+1)/4

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Solution for (3x+5)/6+(x-11)/6=(x+1)/4 equation: 



(3x+5)/6+(x-11)/6=(x+1)/4

We move all terms to the left:

(3x+5)/6+(x-11)/6-((x+1)/4)=0

We calculate fractions


4x/()+(-((x+1)*6)/()=0



We calculate terms in parentheses: +(-((x+1)*6)/(), so:

-((x+1)*6)/(

We multiply all the terms by the denominator


-((x+1)*6)



We calculate terms in parentheses: -((x+1)*6), so:

(x+1)*6

We multiply parentheses

6x+6

Back to the equation:

-(6x+6)



We get rid of parentheses

-6x-6

Back to the equation:

+(-6x-6)



We get rid of parentheses

4x/()-6x-6=0

We multiply all the terms by the denominator


4x-6x*()-6*()=0

We add all the numbers together, and all the variables

4x-6x*()=0

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