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(3x+5)/8x(2x)=x
We move all terms to the left:
(3x+5)/8x(2x)-(x)=0
Domain of the equation: 8x2x!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
-1x+(3x+5)/8x2x=0
We multiply all the terms by the denominator
-1x*8x2x+(3x+5)=0
Wy multiply elements
-8x^3+(3x+5)=0
We get rid of parentheses
-8x^3+3x+5=0
We do not support expression: x^3
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