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(3x+5)4x=88
We move all terms to the left:
(3x+5)4x-(88)=0
We multiply parentheses
12x^2+20x-88=0
a = 12; b = 20; c = -88;
Δ = b2-4ac
Δ = 202-4·12·(-88)
Δ = 4624
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4624}=68$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-68}{2*12}=\frac{-88}{24} =-3+2/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+68}{2*12}=\frac{48}{24} =2 $
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