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(3x+5)=(x+3-4x+2)
We move all terms to the left:
(3x+5)-((x+3-4x+2))=0
We add all the numbers together, and all the variables
(3x+5)-((-3x+5))=0
We get rid of parentheses
3x-((-3x+5))+5=0
We calculate terms in parentheses: -((-3x+5)), so:We get rid of parentheses
(-3x+5)
We get rid of parentheses
-3x+5
Back to the equation:
-(-3x+5)
3x+3x-5+5=0
We add all the numbers together, and all the variables
6x=0
x=0/6
x=0
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