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(3x+5+10)=2(x+5+10)
We move all terms to the left:
(3x+5+10)-(2(x+5+10))=0
We add all the numbers together, and all the variables
(3x+15)-(2(x+15))=0
We get rid of parentheses
3x-(2(x+15))+15=0
We calculate terms in parentheses: -(2(x+15)), so:We get rid of parentheses
2(x+15)
We multiply parentheses
2x+30
Back to the equation:
-(2x+30)
3x-2x-30+15=0
We add all the numbers together, and all the variables
x-15=0
We move all terms containing x to the left, all other terms to the right
x=15
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