(3x+50)=(4x+32)

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Solution for (3x+50)=(4x+32) equation: 



(3x+50)=(4x+32)

We move all terms to the left:

(3x+50)-((4x+32))=0

We get rid of parentheses

3x-((4x+32))+50=0



We calculate terms in parentheses: -((4x+32)), so:

(4x+32)

We get rid of parentheses

4x+32

Back to the equation:

-(4x+32)



We get rid of parentheses

3x-4x-32+50=0

We add all the numbers together, and all the variables

-1x+18=0

We move all terms containing x to the left, all other terms to the right

-x=-18

x=-18/-1

x=+18

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