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(3x+6)(2x+1)=0
We multiply parentheses ..
(+6x^2+3x+12x+6)=0
We get rid of parentheses
6x^2+3x+12x+6=0
We add all the numbers together, and all the variables
6x^2+15x+6=0
a = 6; b = 15; c = +6;
Δ = b2-4ac
Δ = 152-4·6·6
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{81}=9$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-9}{2*6}=\frac{-24}{12} =-2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+9}{2*6}=\frac{-6}{12} =-1/2 $
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