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(3x+6)(2x-12)=0
We multiply parentheses ..
(+6x^2-36x+12x-72)=0
We get rid of parentheses
6x^2-36x+12x-72=0
We add all the numbers together, and all the variables
6x^2-24x-72=0
a = 6; b = -24; c = -72;
Δ = b2-4ac
Δ = -242-4·6·(-72)
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2304}=48$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-48}{2*6}=\frac{-24}{12} =-2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+48}{2*6}=\frac{72}{12} =6 $
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