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(3x+6)(5x+2)=255
We move all terms to the left:
(3x+6)(5x+2)-(255)=0
We multiply parentheses ..
(+15x^2+6x+30x+12)-255=0
We get rid of parentheses
15x^2+6x+30x+12-255=0
We add all the numbers together, and all the variables
15x^2+36x-243=0
a = 15; b = 36; c = -243;
Δ = b2-4ac
Δ = 362-4·15·(-243)
Δ = 15876
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{15876}=126$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-126}{2*15}=\frac{-162}{30} =-5+2/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+126}{2*15}=\frac{90}{30} =3 $
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