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(3x+6)(x-7)=0
We multiply parentheses ..
(+3x^2-21x+6x-42)=0
We get rid of parentheses
3x^2-21x+6x-42=0
We add all the numbers together, and all the variables
3x^2-15x-42=0
a = 3; b = -15; c = -42;
Δ = b2-4ac
Δ = -152-4·3·(-42)
Δ = 729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{729}=27$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-27}{2*3}=\frac{-12}{6} =-2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+27}{2*3}=\frac{42}{6} =7 $
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