(3x+6)+41+(6x-5)+(4x+7)+62(7x-11)=

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Solution for (3x+6)+41+(6x-5)+(4x+7)+62(7x-11)= equation:



(3x+6)+41+(6x-5)+(4x+7)+62(7x-11)=
We move all terms to the left:
(3x+6)+41+(6x-5)+(4x+7)+62(7x-11)-()=0
We add all the numbers together, and all the variables
(3x+6)+(6x-5)+(4x+7)+62(7x-11)=0
We multiply parentheses
(3x+6)+(6x-5)+(4x+7)+434x-682=0
We get rid of parentheses
3x+6x+4x+434x+6-5+7-682=0
We add all the numbers together, and all the variables
447x-674=0
We move all terms containing x to the left, all other terms to the right
447x=674
x=674/447
x=1+227/447

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