(3x+6)+41+(6x-5)+(4x+7)+62(7x-11)=90

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Solution for (3x+6)+41+(6x-5)+(4x+7)+62(7x-11)=90 equation: 



(3x+6)+41+(6x-5)+(4x+7)+62(7x-11)=90

We move all terms to the left:

(3x+6)+41+(6x-5)+(4x+7)+62(7x-11)-(90)=0

We add all the numbers together, and all the variables

(3x+6)+(6x-5)+(4x+7)+62(7x-11)-49=0

We multiply parentheses

(3x+6)+(6x-5)+(4x+7)+434x-682-49=0

We get rid of parentheses

3x+6x+4x+434x+6-5+7-682-49=0

We add all the numbers together, and all the variables

447x-723=0

We move all terms containing x to the left, all other terms to the right

447x=723

x=723/447

x=1+92/149

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