(3x+6)+41+(6x-5)+62+(7x-11)+(4x+7)=720

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Solution for (3x+6)+41+(6x-5)+62+(7x-11)+(4x+7)=720 equation: 



(3x+6)+41+(6x-5)+62+(7x-11)+(4x+7)=720

We move all terms to the left:

(3x+6)+41+(6x-5)+62+(7x-11)+(4x+7)-(720)=0

We add all the numbers together, and all the variables

(3x+6)+(6x-5)+(7x-11)+(4x+7)-617=0

We get rid of parentheses

3x+6x+7x+4x+6-5-11+7-617=0

We add all the numbers together, and all the variables

20x-620=0

We move all terms containing x to the left, all other terms to the right

20x=620

x=620/20

x=31

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