(3x+6)/7=(1-x)/5

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Solution for (3x+6)/7=(1-x)/5 equation:



(3x+6)/7=(1-x)/5
We move all terms to the left:
(3x+6)/7-((1-x)/5)=0
We add all the numbers together, and all the variables
(3x+6)/7-((-1x+1)/5)=0
We calculate fractions
3x/()+(-((-1x+1)*7)/()=0
We calculate terms in parentheses: +(-((-1x+1)*7)/(), so:
-((-1x+1)*7)/(
We multiply all the terms by the denominator
-((-1x+1)*7)
We calculate terms in parentheses: -((-1x+1)*7), so:
(-1x+1)*7
We multiply parentheses
-7x+7
Back to the equation:
-(-7x+7)
We get rid of parentheses
7x-7
Back to the equation:
+(7x-7)
We get rid of parentheses
3x/()+7x-7=0
We multiply all the terms by the denominator
3x+7x*()-7*()=0
We add all the numbers together, and all the variables
3x+7x*()=0

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