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(3x+6)=(2x+-11)
We move all terms to the left:
(3x+6)-((2x+-11))=0
We add all the numbers together, and all the variables
(3x+6)-((2x-11))=0
We get rid of parentheses
3x-((2x-11))+6=0
We calculate terms in parentheses: -((2x-11)), so:We get rid of parentheses
(2x-11)
We get rid of parentheses
2x-11
Back to the equation:
-(2x-11)
3x-2x+11+6=0
We add all the numbers together, and all the variables
x+17=0
We move all terms containing x to the left, all other terms to the right
x=-17
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