(3x+6)=(2x+18)+(24)

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Solution for (3x+6)=(2x+18)+(24) equation: 



(3x+6)=(2x+18)+(24)

We move all terms to the left:

(3x+6)-((2x+18)+(24))=0

We get rid of parentheses

3x-((2x+18)+24)+6=0



We calculate terms in parentheses: -((2x+18)+24), so:

(2x+18)+24

We get rid of parentheses

2x+18+24

We add all the numbers together, and all the variables

2x+42

Back to the equation:

-(2x+42)



We get rid of parentheses

3x-2x-42+6=0

We add all the numbers together, and all the variables

x-36=0

We move all terms containing x to the left, all other terms to the right

x=36

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