(3x+6)=(2x-5)+47

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Solution for (3x+6)=(2x-5)+47 equation: 



(3x+6)=(2x-5)+47

We move all terms to the left:

(3x+6)-((2x-5)+47)=0

We get rid of parentheses

3x-((2x-5)+47)+6=0



We calculate terms in parentheses: -((2x-5)+47), so:

(2x-5)+47

We get rid of parentheses

2x-5+47

We add all the numbers together, and all the variables

2x+42

Back to the equation:

-(2x+42)



We get rid of parentheses

3x-2x-42+6=0

We add all the numbers together, and all the variables

x-36=0

We move all terms containing x to the left, all other terms to the right

x=36

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